## Saturday, September 1, 2018

### #The solution in Python3 is as follows:

def solve(n, a, d, m):
count = 0
for i in range(0,n):
total = sum(a[i:m+i])
if total == d:
count+=1
return count
n=int(input())
a=list(map(int,input().split()))
d,m=map(int,input().split())
print(solve(n,a,d,m))

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## Monday, August 13, 2018

### #The solution in Python3 is as follows:

ALICE = 'Alice'
BOB = 'Bob'
def lolo(N):
return ALICE

def init():
T = input()
for num_testcases in range(int(T)):
A = int(input())
x = lolo(A)
print(x)
init()

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### #The solution in Python3 is as follows:

n=int(input())
a=list(map(int,input().split()))
b=set(a)
c=0
for i in b:
if a.count(i)//2>=1:
c+=(a.count(i)//2)
print(c)

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## Monday, August 6, 2018

### #The solution in Python3 is as follows:

n,k=map(int,input().split())
a=list(map(int,input().split()))
b=int(input())
bac=(sum(a)-a[k])//2
if bac==b:
print("Bon Appetit")
elif bac<b:
print(b-bac)

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### #The solution in Python3 is as follows:

n=int(input())
p=int(input())
if (n%2!=0 and p%2!=0) or (n%2!=0 and p%2==0) or (n%2==0 and p%2==0):
print(min(p//2,(n-p)//2))
elif n%2==0 and p%2!=0:
print(min(p//2,((n-p)//2)+1))

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## Wednesday, August 1, 2018

### #The solution in Python3 is as follows:

m = 
for i in range(int(input())-1):
m.append(int(3*m[i]/2))
print(sum(m))

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## Sunday, July 29, 2018

### #The solution in Python3 is as follows:

n,m=map(int,input().split())
a=list(map(int,input().split()))
if m in a:
b=len(a) - a[::-1].index(m) - 1
print(b+1)
else:
print(-1)

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